Respiratory System Practice Questions

Q: Hering-Breuer reflexes are mediated by which of the following?

Slowly adapting myelinated vagal fibers. ### Explanation The **Hering-Breuer Inflation Reflex** is a protective mechanism that prevents over-inflation of the lungs. When the tidal volume exceeds a certain threshold (typically >1.5 liters in adults), it triggers a termination of inspiration to prevent alveolar damage. **1. Why Option A is Correct:** The receptors for this reflex are **Stretch Receptors** located in the smooth muscles of the bronchi and bronchioles. These are **Slowly Adapting Receptors (SARs)**. When stimulated by lung expansion, they send inhibitory signals via **myelinated vagal afferents** to the Inspiratory Center (Dorsal Respiratory Group) in the medulla. This inhibits further inspiration and facilitates expiration. **2. Why Other Options are Incorrect:** * **Option B (Rapidly Adapting Receptors/RARs):** These are "Irritant Receptors" located in the airway epithelium. They respond to noxious gases, smoke, or dust, causing cough, bronchoconstriction, and mucus secretion. * **Option C (Pulmonary C fibers):** These are located in the alveolar walls (Juxta-capillary or **J-receptors**). They are stimulated by pulmonary congestion or edema, leading to the "J-reflex" (rapid shallow breathing, bradycardia, and hypotension). * **Option D (Bronchial C fibers):** These are located in the bronchial walls and respond primarily to chemical mediators (like histamine), leading to bronchoconstriction and rapid shallow breathing. **High-Yield NEET-PG Pearls:** * **Hering-Breuer Deflation Reflex:** Triggered by lung collapse; it stimulates inspiration to prevent atelectasis. * **Vagotomy Effect:** Bilateral vagal sectioning results in **slow and deep breathing** because the inhibitory feedback from stretch receptors is lost. * **Threshold:** In normal resting breathing, the Hering-Breuer reflex is largely inactive in humans; it becomes significant during exercise or in infants.

Q: What is the principal component of surfactant that reduces surface tension in the alveoli and keeps them inflated and non-collapsed?

Dipalmitoyl phosphatidylcholine. **Explanation:** The primary function of pulmonary surfactant is to reduce surface tension at the air-liquid interface of the alveoli, preventing their collapse (atelectasis) during expiration and increasing lung compliance. **Why Dipalmitoyl phosphatidylcholine (DPPC) is correct:** DPPC, also known as **Lecithin**, is the most abundant and functionally significant component of surfactant, accounting for approximately **60-70%** of its total phospholipid content. It is an amphipathic molecule; its hydrophobic fatty acid tails point toward the air, while the hydrophilic heads point toward the alveolar lining fluid. This orientation allows DPPC to displace water molecules, effectively lowering surface tension. **Analysis of Incorrect Options:** * **B. Phosphatidylglycerol (PG):** While PG is the second most abundant phospholipid in surfactant (approx. 10%), it is not the "principal" component. Its clinical significance lies in fetal lung maturity; its presence in amniotic fluid is a marker of mature surfactant production. * **C. Carbohydrate component:** Surfactant contains a very small percentage of carbohydrates (approx. 2%), which are generally parts of glycoproteins and do not contribute significantly to surface tension reduction. * **D. Lipopolysaccharide:** This is a component of the cell wall of Gram-negative bacteria (endotoxin) and is not a constituent of normal pulmonary surfactant. **High-Yield Clinical Pearls for NEET-PG:** * **Source:** Surfactant is synthesized and secreted by **Type II Pneumocytes**. * **Storage:** It is stored in intracellular organelles called **Lamellar bodies**. * **L/S Ratio:** A Lecithin/Sphingomyelin ratio **> 2.0** in amniotic fluid indicates fetal lung maturity. * **Clinical Correlation:** Deficiency of surfactant in premature infants leads to **Infant Respiratory Distress Syndrome (IRDS)** or Hyaline Membrane Disease.

Q: Which of the following statements is true about the Hb-O2 dissociation curve?

Fetal hemoglobin shifts the curve to the left.. The Hemoglobin-Oxygen (Hb-O₂) dissociation curve describes the relationship between the partial pressure of oxygen ($PO_2$) and the percentage saturation of hemoglobin. ### **Correct Option: A** **Fetal Hemoglobin (HbF)** has a higher affinity for oxygen than adult hemoglobin (HbA). This is because HbF does not bind effectively to **2,3-BPG**, a molecule that normally stabilizes the "Tense" (deoxygenated) state of hemoglobin. This higher affinity ensures that oxygen is transferred from maternal blood to fetal blood across the placenta. On the graph, increased affinity is represented by a **Left Shift** (lower $P_{50}$). ### **Incorrect Options:** * **B. Hypothermia:** A decrease in temperature stabilizes the bond between Hb and $O_2$, increasing affinity and shifting the curve to the **Left**. Hyperthermia (fever) shifts it to the right. * **C. Hypercarbia:** Increased $CO_2$ levels (and the resulting decrease in pH) decrease Hb-O₂ affinity, shifting the curve to the **Right**. This is known as the **Bohr Effect**, which facilitates $O_2$ unloading in metabolically active tissues. * **D. Left Shift:** A left shift indicates increased affinity, meaning hemoglobin holds onto oxygen more tightly. Therefore, a left shift results in **decreased** oxygen release to the tissues. ### **High-Yield Clinical Pearls for NEET-PG:** * **Right Shift (CADET, face Right!):** **C**O₂, **A**cidosis, **D**PG (2,3-BPG), **E**xercise, and **T**emperature increase. A right shift means oxygen is "given away" more easily. * **$P_{50}$ Value:** The $PO_2$ at which Hb is 50% saturated. Normal adult $P_{50}$ is **26.6 mmHg**. A right shift increases $P_{50}$; a left shift decreases it. * **Carbon Monoxide (CO):** CO shifts the curve to the **Left** (interfering with unloading) and also decreases the oxygen-carrying capacity (plateau height).

Q: A 20-year-old medical student has the following data: tidal volume = 540 mL, partial pressure of CO2 in expired air (PECO2) = 20 mm Hg, partial pressure of CO2 in arterial blood (PACO2) = 30 mm Hg, and respiratory rate = 15/min. Calculate the alveolar ventilation.

5.4 L/min. To solve this problem, we must first calculate the **Physiological Dead Space ($V_D$)** using the **Bohr equation**, and then use that to find the **Alveolar Ventilation ($\dot{V}_A$)**. ### 1. Calculation Steps * **Step 1: Find Dead Space ($V_D$)** Using the Bohr equation: $V_D = V_T \times \frac{PaCO_2 - PECO_2}{PaCO_2}$ $V_D = 540 \times \frac{30 - 20}{30} = 540 \times \frac{10}{30} = 180 \text{ mL}$. * **Step 2: Find Alveolar Volume ($V_A$)** $V_A = V_T - V_D = 540 - 180 = 360 \text{ mL}$. * **Step 3: Calculate Alveolar Ventilation ($\dot{V}_A$)** $\dot{V}_A = V_A \times \text{Respiratory Rate}$ $\dot{V}_A = 360 \text{ mL} \times 15/\text{min} = 5,400 \text{ mL/min} = \mathbf{5.4 \text{ L/min}}$. ### 2. Analysis of Options * **Option D (Correct):** Correctly accounts for the physiological dead space (1/3 of $V_T$) before multiplying by the respiratory rate. * **Option A (4.2 L/min):** This value is too low and would result if the dead space was overestimated. * **Option B (4.8 L/min):** Incorrect calculation; often reached if a standard dead space of 150 mL is assumed instead of using the provided $CO_2$ data. * **Option C (5.2 L/min):** Mathematical error in the Bohr equation application. ### 3. Clinical Pearls for NEET-PG * **Physiological vs. Anatomical Dead Space:** In healthy individuals, they are nearly equal. However, in diseases like Pulmonary Embolism, physiological dead space increases significantly. * **Bohr Equation:** It specifically measures **Physiological Dead Space**. It uses $PaCO_2$ (arterial) because it represents the $CO_2$ level in functional alveoli. * **High-Yield Fact:** If $PECO_2$ is 0, the dead space equals the tidal volume (total wasted ventilation).

Q: A 32-year-old patient has a pulmonary vascular resistance of 4 mm Hg/L per minute and a cardiac output of 5 L/min. What is the driving pressure for moving blood through the pulmonary circulation?

20 mm Hg. ### Explanation **1. Understanding the Correct Answer (C: 20 mm Hg)** The relationship between pressure, flow, and resistance in the pulmonary circulation is governed by **Ohm’s Law**, which states: **Pressure (Driving Pressure) = Flow (Cardiac Output) × Resistance** In this clinical scenario: * **Cardiac Output (Q):** 5 L/min * **Pulmonary Vascular Resistance (PVR):** 4 mm Hg/L/min By applying the formula: **Driving Pressure = 5 L/min × 4 mm Hg/L/min = 20 mm Hg.** The "driving pressure" in pulmonary circulation represents the pressure gradient required to move blood from the pulmonary artery to the left atrium (Mean Pulmonary Artery Pressure minus Left Atrial Pressure). **2. Analysis of Incorrect Options** * **Option A (10 mm Hg):** This value is too low. It would result if the resistance were only 2 mm Hg/L/min at the same cardiac output. * **Option B (15 mm Hg):** This is a common distractor representing the average Mean Pulmonary Artery Pressure (mPAP) in a healthy individual, but it does not satisfy the mathematical product of the given variables. * **Option C (30 mm Hg):** This value is too high. A driving pressure of 30 mm Hg at a cardiac output of 5 L/min would imply a PVR of 6 mm Hg/L/min, indicating pulmonary hypertension. **3. Clinical Pearls & High-Yield Facts** * **Normal PVR:** In a healthy adult, PVR is significantly lower than Systemic Vascular Resistance (SVR)—usually about **1/10th** of SVR. * **Recruitment and Distension:** The pulmonary bed is highly compliant. When cardiac output increases (e.g., during exercise), PVR actually **decreases** due to the recruitment of collapsed capillaries and the distension of open ones. * **Pulmonary Hypertension Definition:** Defined as a Mean Pulmonary Artery Pressure **>20 mm Hg** at rest (updated from the previous 25 mm Hg threshold).

Q: Which of the following statements regarding alveolar epithelial cells is true?

Type III pneumocytes function as chemoreceptors.. ### Explanation **Correct Answer: C. Type III pneumocytes function as chemoreceptors.** **1. Why the Correct Answer is Right:** Type III pneumocytes, also known as **Alveolar Brush Cells**, are specialized cells found in the alveolar wall. Unlike Type I and II cells, they are characterized by apical microvilli and are associated with afferent nerve endings. Current physiological research indicates they function as **chemoreceptors**, sensing the chemical composition of the alveolar environment and potentially playing a role in regulating breathing or local immune responses. **2. Analysis of Incorrect Options:** * **Option A:** Gas exchange occurs primarily across **Type I pneumocytes**. These are thin, squamous cells covering ~95% of the alveolar surface area, optimized for diffusion. * **Option B:** **Lamellar inclusion bodies** are characteristic of **Type II pneumocytes**. These bodies store and secrete pulmonary surfactant, which reduces surface tension. * **Option D:** In the human lung, **Type II pneumocytes are more numerous** than Type I cells, but the ratio is approximately **60:40 (or 3:2)**, not 2:1. Despite being more numerous, Type II cells occupy only 5% of the surface area due to their cuboidal shape. **3. High-Yield Clinical Pearls for NEET-PG:** * **Type I Pneumocytes:** Extremely susceptible to injury; they **cannot replicate**. * **Type II Pneumocytes:** Act as the **"Stem Cells"** of the alveoli; they proliferate and differentiate into Type I cells following lung injury. * **Surfactant:** Production begins at 24–28 weeks of gestation, but adequate levels are usually reached only after **35 weeks**. * **Blood-Air Barrier:** Composed of Type I pneumocytes, fused basement membrane, and capillary endothelial cells.

Q: What is true about pneumothorax?

Total chest wall diameter is increased. In the normal respiratory system, the lung and the chest wall are held together by the negative intrapleural pressure. The lung has a natural tendency to **recoil inward**, while the chest wall has a natural tendency to **expand outward**. ### Why Option A is Correct In a **pneumothorax**, air enters the pleural space, breaking the vacuum (negative pressure) that holds the two structures together. Once this "tether" is lost: 1. The lung collapses toward the hilum due to its elastic recoil. 2. The chest wall, no longer held inward by the lung’s recoil, springs outward to its natural resting position. This results in an **increased total chest wall diameter** on the affected side. ### Why Other Options are Incorrect * **B. Intrapleural pressure becomes more negative:** In pneumothorax, intrapleural pressure becomes **less negative** (moves toward atmospheric pressure or becomes positive in tension pneumothorax). * **C. Concentration of surfactant:** Surfactant production is a function of Type II pneumocytes. While a collapsed lung may have atelectasis, pneumothorax does not primarily reduce the concentration of surfactant. * **D. Increased lung compliance:** Compliance is the ease with which the lung expands. In pneumothorax, the lung collapses and becomes much harder to inflate, leading to **decreased** lung compliance. ### High-Yield Clinical Pearls for NEET-PG * **Tension Pneumothorax:** Characterized by a "one-way valve" mechanism where pressure exceeds atmospheric pressure, leading to **mediastinal shift** to the opposite side and hypotension. * **Percussion Note:** Hyper-resonant (due to air in the pleural space). * **Breath Sounds:** Absent or significantly diminished on the affected side. * **X-ray finding:** Presence of a visceral pleural line with an absence of peripheral lung markings.

Question 1

Hering-Breuer reflexes are mediated by which of the following?

Accepted Answer

Slowly adapting myelinated vagal fibers

Answer

Rapidly adapting myelinated vagal fibers

Answer

Unmyelinated pulmonary C fibers

Answer

Unmyelinated bronchial C fibers

Question 2

What is the principal component of surfactant that reduces surface tension in the alveoli and keeps them inflated and non-collapsed?

Accepted Answer

Dipalmitoyl phosphatidylcholine

Answer

Phosphatidylglycerol

Answer

Carbohydrate component

Answer

Lipopolysaccharide

Question 3

Which of the following statements is true about the Hb-O2 dissociation curve?

Accepted Answer

Fetal hemoglobin shifts the curve to the left.

Answer

Hypothermia shifts the curve to the right.

Answer

Hypercarbia shifts the curve to the left.

Answer

A left shift causes increased oxygen release.

Question 4

A 20-year-old medical student has the following data: tidal volume = 540 mL, partial pressure of CO2 in expired air (PECO2) = 20 mm Hg, partial pressure of CO2 in arterial blood (PACO2) = 30 mm Hg, and respiratory rate = 15/min. Calculate the alveolar ventilation.

Accepted Answer

5.4 L/min

Answer

4.2 L/min

Answer

4.8 L/min

Answer

5.2 L/min

Question 5

A 32-year-old patient has a pulmonary vascular resistance of 4 mm Hg/L per minute and a cardiac output of 5 L/min. What is the driving pressure for moving blood through the pulmonary circulation?

Accepted Answer

20 mm Hg

Answer

10 mm Hg

Answer

15 mm Hg

Answer

30 mm Hg

Question 6

Which of the following statements regarding alveolar epithelial cells is true?

Accepted Answer

Type III pneumocytes function as chemoreceptors.

Answer

Gas exchange occurs primarily across type II pneumocytes.

Answer

Lamellar inclusion bodies are characteristic of type I pneumocytes.

Answer

Type II and type I pneumocytes exist in a ratio of approximately 2:1.

Question 7

What is the physiological dead space when arterial PCO2 (PaCO2) is 48mmHg, expired PCO2 (PECO2) is 25mmHg, and tidal volume is 500ml?

Accepted Answer

260ml

Answer

240ml

Answer

220ml

Answer

200ml

Question 8

What is true about pneumothorax?

Accepted Answer

Total chest wall diameter is increased

Answer

Intrapleural pressure becomes more negative

Answer

The concentration of surfactant is reduced in alveoli

Answer

Increased lung compliance

Question 9

True about inspiration, the intrapleural pressure becomes?

Accepted Answer

More negative

Answer

More positive

Answer

Same

Answer

No relation

Question 10

Bronchial calibre is reduced by:

Accepted Answer

Stimulation of parasympathetic fiber

Answer

Beta 2 receptor stimulation

Answer

Stimulation of sympathetic fiber

Answer

Alpha 2 receptor stimulation

Respiratory System — MCQs

Respiratory System — MCQs

On this page

Practice by Chapter

Want unlimited practice?