Aldehyde dehydrogenase requires NAD as ?
Type of inhibition of aconitase by trans-aconitate is?
Which of the following represents the most significant regulatory control point among these TCA cycle reactions?
Fluoroacetate inhibits?
Methionine can enter the TCA cycle at which level?
In ETC NADH generates -
Glucose is converted to glucuronate by which process?
Which of the following is an amino sugar formed from fructose-6-phosphate?
Which of the following is a true difference between gangliosides and cerebrosides?
Which of the following pairs of compounds has the highest standard reduction potential?
NEET-PG 2012 - Biochemistry NEET-PG Practice Questions and MCQs
Question 61: Aldehyde dehydrogenase requires NAD as ?
- A. None of the options
- B. Apoenzyme
- C. Coenzyme (Correct Answer)
- D. Cofactor
Explanation: ***Coenzyme*** - **NAD** (nicotinamide adenine dinucleotide) acts as a **coenzyme** for aldehyde dehydrogenase, serving as the **most specific and accurate classification** for its role. - As a coenzyme, **NAD** is an **organic, non-protein molecule** that binds reversibly to the enzyme and acts as a **transient carrier of electrons** (hydride ions, H⁻) during aldehyde oxidation. - **NAD⁺** accepts electrons from the aldehyde substrate, becoming reduced to **NADH**, which then dissociates and transfers electrons elsewhere in metabolism. - This is the **preferred answer** because coenzyme precisely describes NAD's organic nature, vitamin origin (niacin/B3), and its role as a mobile electron carrier. *Cofactor* - While technically **NAD is a type of cofactor** (cofactors include coenzymes, prosthetic groups, and metal ions), this term is **too general** for this context. - In biochemistry nomenclature, when both a general and specific term apply, the **more specific term (coenzyme) is preferred** to demonstrate precise understanding. - Choosing "cofactor" would be like calling a "cardiologist" a "doctor" - true but less specific. *Apoenzyme* - An **apoenzyme** is the **protein component** of an enzyme without its cofactor - it refers to the enzyme itself, not to NAD. - In this case, **aldehyde dehydrogenase** (the protein) is the apoenzyme, and **NAD** is the coenzyme that binds to it. - Together they form the active **holoenzyme** (apoenzyme + coenzyme = holoenzyme). *None of the options* - Incorrect because **coenzyme** is the accurate and specific term for NAD's role in aldehyde dehydrogenase function.
Question 62: Type of inhibition of aconitase by trans-aconitate is?
- A. Competitive (Correct Answer)
- B. Non-competitive
- C. Allosteric
- D. None of the options
Explanation: ***Competitive*** - **Competitive inhibition** occurs when the inhibitor (trans-aconitate) structurally resembles the enzyme's natural substrate (cis-aconitate) and binds to the **active site**, preventing the substrate from binding. - This type of inhibition can be overcome by increasing the concentration of the **substrate**. *Non-competitive* - **Non-competitive inhibitors** bind to a site on the enzyme other than the active site, causing a conformational change that reduces the enzyme's efficiency, regardless of substrate concentration. - Trans-aconitate's structural similarity to aconitate's substrate points away from a non-competitive mechanism. *Allosteric* - **Allosteric inhibition** involves an inhibitor binding to a regulatory site (allosteric site) on the enzyme, which is distinct from the active site, to alter enzyme activity. - While allosteric regulation is a type of non-competitive inhibition, trans-aconitate's direct structural resemblance to the substrate makes competitive inhibition the more specific and accurate description. *None of the options* - This option is incorrect because **competitive inhibition** accurately describes the mechanism by which trans-aconitate inhibits aconitase, given its structural similarity to the natural substrate. - The other options are less fitting due to the specific characteristics of trans-aconitate's action.
Question 63: Which of the following represents the most significant regulatory control point among these TCA cycle reactions?
- A. Succinyl-CoA to Succinate (Succinyl-CoA synthetase)
- B. Isocitrate to Alpha-ketoglutarate (Isocitrate dehydrogenase) (Correct Answer)
- C. Acetyl-CoA + Oxaloacetate to Citrate (Citrate synthase)
- D. Alpha-ketoglutarate to Succinyl-CoA (Alpha-ketoglutarate dehydrogenase complex)
Explanation: ***Isocitrate to Alpha-ketoglutarate (Isocitrate dehydrogenase)*** - **Isocitrate dehydrogenase** is the **rate-limiting enzyme** and the **most significant regulatory control point** of the TCA cycle - It catalyzes the first **irreversible NADH-generating step** after citrate formation, making it the key determinant of cycle flux - Strongly **activated by ADP** (indicating low energy status) and **Ca²⁺** (in mitochondria) - Strongly **inhibited by NADH and ATP** (indicating high energy status), providing sensitive energy-status regulation - This is the primary control point recognized in standard biochemistry references *Alpha-ketoglutarate to Succinyl-CoA (Alpha-ketoglutarate dehydrogenase complex)* - The **alpha-ketoglutarate dehydrogenase complex** is an important regulatory enzyme with irreversible catalysis - Inhibited by its products **NADH** and **succinyl-CoA**, as well as by **ATP** - While it is one of the three main control points, it is considered a **secondary regulatory site** compared to isocitrate dehydrogenase *Acetyl-CoA + Oxaloacetate to Citrate (Citrate synthase)* - **Citrate synthase** catalyzes the first committed step of the TCA cycle and is the entry point for acetyl-CoA - Subject to **product inhibition by citrate** and allosteric inhibition by **ATP, NADH, and succinyl-CoA** - Although highly regulated and crucial for initiating the cycle, it is not the rate-limiting step *Succinyl-CoA to Succinate (Succinyl-CoA synthetase)* - This reaction involves **substrate-level phosphorylation** to produce **GTP (or ATP)** - It is a **reversible reaction** and generally not a primary regulatory step - Regulation depends mainly on substrate availability rather than complex allosteric control mechanisms
Question 64: Fluoroacetate inhibits?
- A. Citrate synthase
- B. Succinate dehydrogenase
- C. Alpha-ketoglutarate dehydrogenase
- D. Aconitase (Correct Answer)
Explanation: ***Aconitase*** - **Fluoroacetate** is metabolically converted to **fluorocitrate**, which is a potent competitive inhibitor of **aconitase**. - **Aconitase** is the enzyme responsible for converting **citrate to isocitrate** in the **Krebs cycle**, and its inhibition blocks the cycle. *Citrate synthase* - This enzyme is responsible for the formation of **citrate** from **acetyl-CoA** and **oxaloacetate**. - While fluoroacetate indirectly affects the cycle, it does not directly inhibit **citrate synthase**. *Succinate dehydrogenase* - This enzyme is part of the **Krebs cycle** and the **electron transport chain**, converting **succinate to fumarate**. - **Malonate** is a competitive inhibitor of succinate dehydrogenase, not **fluoroacetate**. *Alpha-ketoglutarate dehydrogenase* - This enzyme catalyzes the conversion of **alpha-ketoglutarate to succinyl-CoA** in the **Krebs cycle**. - Specific inhibitors of this enzyme include **arsenite** and **mercury compounds**, but not fluoroacetate.
Question 65: Methionine can enter the TCA cycle at which level?
- A. Fumarate
- B. Oxaloacetate
- C. Succinyl-CoA (Correct Answer)
- D. Citrate
Explanation: ***Succinyl - CoA*** - Methionine is a **glucogenic amino acid** that is catabolized to propionyl-CoA, which is then converted to **methylmalonyl-CoA** and finally to **succinyl-CoA**. - **Succinyl-CoA** is an intermediate of the **TCA cycle**, allowing methionine-derived carbons to enter the cycle. *Fumarate* - Fumarate is an intermediate of the TCA cycle, but methionine catabolism does not directly produce **fumarate**. - Amino acids like **phenylalanine** and **tyrosine** can be catabolized to fumarate. *Oxaloacetate* - **Oxaloacetate** is a TCA cycle intermediate and can be formed from **pyruvate** (via pyruvate carboxylase) or from certain amino acids like **aspartate** and **asparagine**. - Methionine does not directly convert to oxaloacetate. *Citrate* - **Citrate** is the first intermediate formed in the TCA cycle when **acetyl-CoA** combines with **oxaloacetate**. - Methionine catabolism does not lead to the direct formation of citrate.
Question 66: In ETC NADH generates -
- A. 1 ATPs
- B. 4 ATPs
- C. 3 ATPs (Correct Answer)
- D. 2 ATPs
Explanation: ***3 ATPs*** - Each molecule of **NADH** donates electrons to **Complex I** of the electron transport chain (ETC), resulting in the pumping of enough protons to generate approximately **3 ATP molecules** via **oxidative phosphorylation**. - This high yield is due to NADH's ability to activate multiple proton pumps along the ETC, maximizing the **proton gradient** for ATP synthesis. *1 ATPs* - This is an incorrect yield for NADH; **FADH2** typically generates fewer ATPs (around 2) because it enters the ETC at a later stage, bypassing the initial proton pump. - Generating only 1 ATP from NADH would be very inefficient and is not physiologically accurate for oxidative phosphorylation. *2 ATPs* - While closer, 2 ATPs is the approximate yield for **FADH2**, which enters the ETC at **Complex II**, bypassing Complex I and thus pumping fewer protons. - NADH enters at Complex I, which provides enough energy for a higher ATP yield. *4 ATPs* - 4 ATPs is an overestimation of the ATP yield from NADH in the electron transport chain. - The maximum theoretical yield from NADH via oxidative phosphorylation is typically considered to be 3 ATPs.
Question 67: Glucose is converted to glucuronate by which process?
- A. Oxidation of aldehyde group
- B. Oxidation of both
- C. Oxidation of the terminal alcohol group (Correct Answer)
- D. None of the options
Explanation: ***Oxidation of the terminal alcohol group*** - **Glucuronate** is formed by the **oxidation of the C-6 carbon** (the terminal primary alcohol group) of glucose. - This process is crucial for the detoxification of various substances in the body, as glucuronate is a key component in **glucuronidation reactions**. *Oxidation of aldehyde group* - Oxidation of the **aldehyde group (C-1)** of glucose typically forms **gluconic acid**, not glucuronate. - Gluconate is derived from the oxidation of the first carbon, while glucuronate is derived from the oxidation of the last carbon. *Oxidation of both* - If both the aldehyde group (C-1) and the terminal alcohol group (C-6) of glucose were oxidized, it would result in the formation of **glucaric acid** (saccharic acid), not glucuronate. - Glucaric acid has two carboxyl groups, one at each end of the molecule. *None of the options* - This option is incorrect because the specific biochemical pathway for glucuronate formation involves the oxidation of the terminal alcohol group. - The conversion of glucose to glucuronate is a well-established metabolic process.
Question 68: Which of the following is an amino sugar formed from fructose-6-phosphate?
- A. N-acetylglucosamine-6-phosphate
- B. Glucosamine-6-phosphate (Correct Answer)
- C. Galactosamine-6-phosphate
- D. UDP-N-acetylglucosamine
Explanation: ***Glucosamine-6-phosphate*** - This amino sugar is directly synthesized from **fructose-6-phosphate** via a transamidation reaction, where an amino group replaces a hydroxyl group. - It is a key intermediate in the biosynthesis of other **amino sugars** and **glycosaminoglycans**. *N-acetylglucosamine-6-phosphate* - This is formed from **glucosamine-6-phosphate** by the addition of an **acetyl group**, making it a subsequent product, not the initial amino sugar from fructose-6-phosphate. - The N-acetylation step is crucial for its role in cellular signaling and structural components. *Galactosamine-6-phosphate* - While an amino sugar, **galactosamine-6-phosphate** is derived from UDP-N-acetylglucosamine, not directly from fructose-6-phosphate. - Its formation involves an **epimerization** step of an existing N-acetylglucosamine structure. *UDP-N-acetylglucosamine* - This is an **activated form** of N-acetylglucosamine, formed by the addition of UTP to N-acetylglucosamine-1-phosphate. - It serves as a precursor for the synthesis of complex **carbohydrates** and glycoproteins, far downstream from fructose-6-phosphate.
Question 69: Which of the following is a true difference between gangliosides and cerebrosides?
- A. Specific carbohydrate composition
- B. Charge difference (Correct Answer)
- C. Location in the nervous system
- D. Presence of glucose
Explanation: ***Charge difference*** - **Gangliosides** contain **sialic acid (N-acetylneuraminic acid)** residues, which are negatively charged, making gangliosides **anionic**. - **Cerebrosides** are **neutral glycosphingolipids** as they lack charged sugar residues. *Specific carbohydrate composition* - While both have carbohydrate components, referring to "specific carbohydrate composition" as the *true difference* is too broad. Both have characteristic sugar groups, but the **presence of sialic acid** in gangliosides is the key differentiator in charge. - Cerebrosides typically contain a single sugar (either glucose or galactose), whereas gangliosides have a more complex oligosaccharide chain including sialic acid. *Presence of glucose* - Both cerebrosides (specifically **glucocerebrosides**) and gangliosides can contain **glucose** in their carbohydrate moieties. - This is not a distinguishing feature; the *type* and *arrangement* of sugars, particularly the presence of sialic acid, are more specific. *Location in the nervous system* - Both gangliosides and cerebrosides are abundant in the **nervous system**, particularly in cell membranes. - Their presence in the nervous system is a similarity, not a differentiating factor.
Question 70: Which of the following pairs of compounds has the highest standard reduction potential?
- A. NADH/NAD+
- B. Succinate/Fumarate
- C. Ubiquinone/Ubiquinol
- D. Fe³⁺/Fe²⁺ (Correct Answer)
Explanation: ***Fe³⁺/Fe²⁺*** - The **Fe³⁺/Fe²⁺ couple** has a **standard reduction potential (E'0)** of **+0.77 V**, making it the highest among the given options. - A higher positive E'0 indicates a stronger tendency for the oxidized form to accept electrons and be reduced. *NADH/NAD+* - The **NADH/NAD+ couple** has a **standard reduction potential** of **-0.32 V**, indicating it is a strong reducing agent. - Its negative reduction potential means it readily donates electrons during metabolic processes. *Succinate/Fumarate* - The **succinate/fumarate couple** has a **standard reduction potential** of **+0.03 V**. - This pair is involved in the **TCA cycle**, where succinate is oxidized to fumarate, releasing electrons. *Ubiquinone/Ubiquinol* - The **ubiquinone/ubiquinol couple** has a **standard reduction potential** varying around **+0.05 to +0.10 V**, depending on the specific state. - It acts as a mobile electron carrier in the **electron transport chain**, accepting electrons from NADH and FADH2.