Which vitamin is considered the most potent antioxidant?
In the context of cell membrane composition, what is the typical weight ratio of protein to lipid?
Aldehyde dehydrogenase requires NAD as ?
Type of inhibition of aconitase by trans-aconitate is?
In ETC NADH generates -
Methionine can enter the TCA cycle at which level?
Which of the following represents the most significant regulatory control point among these TCA cycle reactions?
Which enzyme catalyzes the rate limiting step in the TCA cycle?
Glucose is converted to glucuronate by which process?
Which of the following is an amino sugar formed from fructose-6-phosphate?
NEET-PG 2012 - Biochemistry NEET-PG Practice Questions and MCQs
Question 101: Which vitamin is considered the most potent antioxidant?
- A. Vit A
- B. Vit K
- C. Vit E (Correct Answer)
- D. Vit C
Explanation: ***Vit E*** - **Vitamin E** is a **lipid-soluble antioxidant** that primarily protects cell membranes from **oxidative damage** by scavenging free radicals. - Its ability to interrupt **lipid peroxidation** makes it highly effective in protecting tissues rich in polyunsaturated fatty acids, such as cell membranes. *Vit A* - **Vitamin A**, particularly in its carotenoid forms like **beta-carotene**, is an antioxidant, but its primary role is in **vision** and **immune function**. - While it can quench **singlet oxygen** and trap free radicals, it is generally considered less potent than vitamin E in protecting against lipid peroxidation. *Vit K* - **Vitamin K** is crucial for **blood coagulation** and **bone metabolism**, but it does not have significant antioxidant properties. - Its primary biological functions are unrelated to scavenging **free radicals** or preventing oxidative stress. *Vit C* - **Vitamin C** is a potent **water-soluble antioxidant** that works in aqueous environments, such as the cytoplasm and extracellular fluid. - While it can neutralize **reactive oxygen species** and regenerate other antioxidants like vitamin E, its solubility limits its direct activity in protecting lipid membranes, making vitamin E more potent in that specific context.
Question 102: In the context of cell membrane composition, what is the typical weight ratio of protein to lipid?
- A. 1 : 2
- B. 4 : 1
- C. 1 : 1 (Correct Answer)
- D. 2 : 1
Explanation: ***1 : 1*** - The **typical weight ratio of protein to lipid** in most cell membranes is approximately **1:1** (equal by weight). - While the **number of lipid molecules** far exceeds the number of protein molecules, proteins are much larger and heavier, resulting in roughly equal weight contributions. - This **1:1 ratio represents an average** for typical plasma membranes, though it can vary significantly depending on membrane type and function. *1 : 2* - This protein:lipid ratio would indicate **lipids contribute twice as much by weight** as proteins. - This is characteristic of **myelin membranes**, which are specialized for insulation and have exceptionally high lipid content. - However, this is **not typical** of most cell membranes. *2 : 1* - This ratio would suggest **proteins contribute twice as much by weight** as lipids. - While some protein-rich membranes exist, this is **higher than the average** for typical cell membranes. - The typical ratio is closer to 1:1 rather than being protein-dominant at 2:1. *4 : 1* - A 4:1 protein:lipid ratio represents an **extremely protein-rich membrane**. - This is characteristic of the **inner mitochondrial membrane**, which is packed with electron transport chain proteins. - This is a **specialized membrane**, not representative of typical cell membranes.
Question 103: Aldehyde dehydrogenase requires NAD as ?
- A. None of the options
- B. Apoenzyme
- C. Coenzyme (Correct Answer)
- D. Cofactor
Explanation: ***Coenzyme*** - **NAD** (nicotinamide adenine dinucleotide) acts as a **coenzyme** for aldehyde dehydrogenase, serving as the **most specific and accurate classification** for its role. - As a coenzyme, **NAD** is an **organic, non-protein molecule** that binds reversibly to the enzyme and acts as a **transient carrier of electrons** (hydride ions, H⁻) during aldehyde oxidation. - **NAD⁺** accepts electrons from the aldehyde substrate, becoming reduced to **NADH**, which then dissociates and transfers electrons elsewhere in metabolism. - This is the **preferred answer** because coenzyme precisely describes NAD's organic nature, vitamin origin (niacin/B3), and its role as a mobile electron carrier. *Cofactor* - While technically **NAD is a type of cofactor** (cofactors include coenzymes, prosthetic groups, and metal ions), this term is **too general** for this context. - In biochemistry nomenclature, when both a general and specific term apply, the **more specific term (coenzyme) is preferred** to demonstrate precise understanding. - Choosing "cofactor" would be like calling a "cardiologist" a "doctor" - true but less specific. *Apoenzyme* - An **apoenzyme** is the **protein component** of an enzyme without its cofactor - it refers to the enzyme itself, not to NAD. - In this case, **aldehyde dehydrogenase** (the protein) is the apoenzyme, and **NAD** is the coenzyme that binds to it. - Together they form the active **holoenzyme** (apoenzyme + coenzyme = holoenzyme). *None of the options* - Incorrect because **coenzyme** is the accurate and specific term for NAD's role in aldehyde dehydrogenase function.
Question 104: Type of inhibition of aconitase by trans-aconitate is?
- A. Competitive (Correct Answer)
- B. Non-competitive
- C. Allosteric
- D. None of the options
Explanation: ***Competitive*** - **Competitive inhibition** occurs when the inhibitor (trans-aconitate) structurally resembles the enzyme's natural substrate (cis-aconitate) and binds to the **active site**, preventing the substrate from binding. - This type of inhibition can be overcome by increasing the concentration of the **substrate**. *Non-competitive* - **Non-competitive inhibitors** bind to a site on the enzyme other than the active site, causing a conformational change that reduces the enzyme's efficiency, regardless of substrate concentration. - Trans-aconitate's structural similarity to aconitate's substrate points away from a non-competitive mechanism. *Allosteric* - **Allosteric inhibition** involves an inhibitor binding to a regulatory site (allosteric site) on the enzyme, which is distinct from the active site, to alter enzyme activity. - While allosteric regulation is a type of non-competitive inhibition, trans-aconitate's direct structural resemblance to the substrate makes competitive inhibition the more specific and accurate description. *None of the options* - This option is incorrect because **competitive inhibition** accurately describes the mechanism by which trans-aconitate inhibits aconitase, given its structural similarity to the natural substrate. - The other options are less fitting due to the specific characteristics of trans-aconitate's action.
Question 105: In ETC NADH generates -
- A. 1 ATPs
- B. 4 ATPs
- C. 3 ATPs (Correct Answer)
- D. 2 ATPs
Explanation: ***3 ATPs*** - Each molecule of **NADH** donates electrons to **Complex I** of the electron transport chain (ETC), resulting in the pumping of enough protons to generate approximately **3 ATP molecules** via **oxidative phosphorylation**. - This high yield is due to NADH's ability to activate multiple proton pumps along the ETC, maximizing the **proton gradient** for ATP synthesis. *1 ATPs* - This is an incorrect yield for NADH; **FADH2** typically generates fewer ATPs (around 2) because it enters the ETC at a later stage, bypassing the initial proton pump. - Generating only 1 ATP from NADH would be very inefficient and is not physiologically accurate for oxidative phosphorylation. *2 ATPs* - While closer, 2 ATPs is the approximate yield for **FADH2**, which enters the ETC at **Complex II**, bypassing Complex I and thus pumping fewer protons. - NADH enters at Complex I, which provides enough energy for a higher ATP yield. *4 ATPs* - 4 ATPs is an overestimation of the ATP yield from NADH in the electron transport chain. - The maximum theoretical yield from NADH via oxidative phosphorylation is typically considered to be 3 ATPs.
Question 106: Methionine can enter the TCA cycle at which level?
- A. Fumarate
- B. Oxaloacetate
- C. Succinyl-CoA (Correct Answer)
- D. Citrate
Explanation: ***Succinyl - CoA*** - Methionine is a **glucogenic amino acid** that is catabolized to propionyl-CoA, which is then converted to **methylmalonyl-CoA** and finally to **succinyl-CoA**. - **Succinyl-CoA** is an intermediate of the **TCA cycle**, allowing methionine-derived carbons to enter the cycle. *Fumarate* - Fumarate is an intermediate of the TCA cycle, but methionine catabolism does not directly produce **fumarate**. - Amino acids like **phenylalanine** and **tyrosine** can be catabolized to fumarate. *Oxaloacetate* - **Oxaloacetate** is a TCA cycle intermediate and can be formed from **pyruvate** (via pyruvate carboxylase) or from certain amino acids like **aspartate** and **asparagine**. - Methionine does not directly convert to oxaloacetate. *Citrate* - **Citrate** is the first intermediate formed in the TCA cycle when **acetyl-CoA** combines with **oxaloacetate**. - Methionine catabolism does not lead to the direct formation of citrate.
Question 107: Which of the following represents the most significant regulatory control point among these TCA cycle reactions?
- A. Succinyl-CoA to Succinate (Succinyl-CoA synthetase)
- B. Isocitrate to Alpha-ketoglutarate (Isocitrate dehydrogenase) (Correct Answer)
- C. Acetyl-CoA + Oxaloacetate to Citrate (Citrate synthase)
- D. Alpha-ketoglutarate to Succinyl-CoA (Alpha-ketoglutarate dehydrogenase complex)
Explanation: ***Isocitrate to Alpha-ketoglutarate (Isocitrate dehydrogenase)*** - **Isocitrate dehydrogenase** is the **rate-limiting enzyme** and the **most significant regulatory control point** of the TCA cycle - It catalyzes the first **irreversible NADH-generating step** after citrate formation, making it the key determinant of cycle flux - Strongly **activated by ADP** (indicating low energy status) and **Ca²⁺** (in mitochondria) - Strongly **inhibited by NADH and ATP** (indicating high energy status), providing sensitive energy-status regulation - This is the primary control point recognized in standard biochemistry references *Alpha-ketoglutarate to Succinyl-CoA (Alpha-ketoglutarate dehydrogenase complex)* - The **alpha-ketoglutarate dehydrogenase complex** is an important regulatory enzyme with irreversible catalysis - Inhibited by its products **NADH** and **succinyl-CoA**, as well as by **ATP** - While it is one of the three main control points, it is considered a **secondary regulatory site** compared to isocitrate dehydrogenase *Acetyl-CoA + Oxaloacetate to Citrate (Citrate synthase)* - **Citrate synthase** catalyzes the first committed step of the TCA cycle and is the entry point for acetyl-CoA - Subject to **product inhibition by citrate** and allosteric inhibition by **ATP, NADH, and succinyl-CoA** - Although highly regulated and crucial for initiating the cycle, it is not the rate-limiting step *Succinyl-CoA to Succinate (Succinyl-CoA synthetase)* - This reaction involves **substrate-level phosphorylation** to produce **GTP (or ATP)** - It is a **reversible reaction** and generally not a primary regulatory step - Regulation depends mainly on substrate availability rather than complex allosteric control mechanisms
Question 108: Which enzyme catalyzes the rate limiting step in the TCA cycle?
- A. Fumarase
- B. Aconitase
- C. Thiokinase
- D. α-ketoglutarate dehydrogenase (Correct Answer)
Explanation: **α-ketoglutarate dehydrogenase** - The **α-ketoglutarate dehydrogenase complex** catalyzes the oxidative decarboxylation of α-ketoglutarate to succinyl-CoA, producing NADH and CO2. - This step is a **major control point** in the TCA cycle and is highly regulated by: - **Product inhibition**: Succinyl-CoA and NADH - **Calcium ions**: Activate the enzyme - Along with isocitrate dehydrogenase and citrate synthase, it represents one of the three key regulatory enzymes of the TCA cycle. *Fumarase* - **Fumarase** catalyzes the reversible hydration of fumarate to L-malate. - This enzyme is **not a regulatory step** in the TCA cycle; its activity is typically high and not a control point for the overall flux of the cycle. *Aconitase* - **Aconitase** catalyzes the reversible isomerization of citrate to isocitrate, via the intermediate cis-aconitate. - While important for the cycle's progression, aconitase activity is **not considered a rate-limiting step** for the overall regulation of the TCA cycle. *Thiokinase* - The term **thiokinase** (or succinyl-CoA synthetase) catalyzes the reversible conversion of succinyl-CoA to succinate, coupled with GTP/ATP production. - This enzyme is responsible for **substrate-level phosphorylation** in the TCA cycle but does not represent a primary regulatory or rate-limiting step.
Question 109: Glucose is converted to glucuronate by which process?
- A. Oxidation of aldehyde group
- B. Oxidation of both
- C. Oxidation of the terminal alcohol group (Correct Answer)
- D. None of the options
Explanation: ***Oxidation of the terminal alcohol group*** - **Glucuronate** is formed by the **oxidation of the C-6 carbon** (the terminal primary alcohol group) of glucose. - This process is crucial for the detoxification of various substances in the body, as glucuronate is a key component in **glucuronidation reactions**. *Oxidation of aldehyde group* - Oxidation of the **aldehyde group (C-1)** of glucose typically forms **gluconic acid**, not glucuronate. - Gluconate is derived from the oxidation of the first carbon, while glucuronate is derived from the oxidation of the last carbon. *Oxidation of both* - If both the aldehyde group (C-1) and the terminal alcohol group (C-6) of glucose were oxidized, it would result in the formation of **glucaric acid** (saccharic acid), not glucuronate. - Glucaric acid has two carboxyl groups, one at each end of the molecule. *None of the options* - This option is incorrect because the specific biochemical pathway for glucuronate formation involves the oxidation of the terminal alcohol group. - The conversion of glucose to glucuronate is a well-established metabolic process.
Question 110: Which of the following is an amino sugar formed from fructose-6-phosphate?
- A. N-acetylglucosamine-6-phosphate
- B. Glucosamine-6-phosphate (Correct Answer)
- C. Galactosamine-6-phosphate
- D. UDP-N-acetylglucosamine
Explanation: ***Glucosamine-6-phosphate*** - This amino sugar is directly synthesized from **fructose-6-phosphate** via a transamidation reaction, where an amino group replaces a hydroxyl group. - It is a key intermediate in the biosynthesis of other **amino sugars** and **glycosaminoglycans**. *N-acetylglucosamine-6-phosphate* - This is formed from **glucosamine-6-phosphate** by the addition of an **acetyl group**, making it a subsequent product, not the initial amino sugar from fructose-6-phosphate. - The N-acetylation step is crucial for its role in cellular signaling and structural components. *Galactosamine-6-phosphate* - While an amino sugar, **galactosamine-6-phosphate** is derived from UDP-N-acetylglucosamine, not directly from fructose-6-phosphate. - Its formation involves an **epimerization** step of an existing N-acetylglucosamine structure. *UDP-N-acetylglucosamine* - This is an **activated form** of N-acetylglucosamine, formed by the addition of UTP to N-acetylglucosamine-1-phosphate. - It serves as a precursor for the synthesis of complex **carbohydrates** and glycoproteins, far downstream from fructose-6-phosphate.