Optics and Refraction Practice Questions

Q: On performing retinoscopy, in which of the following conditions does the movement of the red reflex not occur with the movement of the retinoscope?

Myopia greater than 1 diopter. ### Explanation The direction of the red reflex during retinoscopy depends on the position of the **far point (punctum remotum)** of the patient's eye relative to the retinoscope (usually performed at a distance of 1 meter). #### Why "Myopia greater than 1 diopter" is correct: Retinoscopy at 1 meter corresponds to a neutral point of 1 Diopter (D). * In **Myopia > 1D**, the far point of the eye lies **between the patient and the retinoscope**. * Because the rays cross before reaching the observer’s eye, the movement of the red reflex is reversed. Therefore, you see an **"Against-movement"** (movement opposite to the retinoscope). #### Why the other options are incorrect: * **A. Emmetropia:** The far point is at infinity. Rays emerging from the eye are parallel, resulting in a **"With-movement."** * **C. Myopia less than 1 diopter:** The far point lies **behind the retinoscope**. Since the rays have not yet converged to a point, the observer sees a **"With-movement."** * **D. Hypermetropia:** The far point is virtual and located behind the eye. Emerging rays are divergent, resulting in a **"With-movement."** #### High-Yield Clinical Pearls for NEET-PG: 1. **The Neutral Point:** This is the point where there is no movement, and the pupil is filled with a static, bright glow. This occurs when the far point of the eye coincides exactly with the retinoscope (e.g., Myopia of exactly 1D when working at 1 meter). 2. **Working Distance Formula:** The final prescription = Retinoscopy value minus the working distance (in Diopters). If working at 66 cm, subtract 1.5D; if at 1 meter, subtract 1D. 3. **Mnemonic:** * **W**ith movement = **H**ypermetropia, **E**mmetropia, **M**yopia 1D (**AM**)

Q: What is the most accepted modality of treatment for 2D myopia in a 13-year-old girl?

Spectacles. **Explanation:** The primary goal in managing pediatric myopia is to provide clear vision while ensuring safety and accommodating the growing eye. **Why Spectacles are the Correct Choice:** In a 13-year-old child, the eye is still undergoing physiological growth, and the refractive power is likely to change until early adulthood (usually 18–21 years). **Spectacles** are the most accepted, non-invasive, and safest modality for a 2D error. They are easy to update as the prescription changes and carry no risk of corneal infection or surgical complications. **Analysis of Incorrect Options:** * **Excimer Laser (LASIK/PRK):** Refractive surgeries are strictly contraindicated in patients under 18 years of age. The cornea and axial length must be stable for at least 12–18 months before considering laser treatment to avoid regression or post-surgical ectasia. * **Contact Lenses:** While an option for older children, they are generally considered secondary to spectacles in a 13-year-old due to the high maintenance required and the risk of **Acanthamoeba or bacterial keratitis** if hygiene is not strictly maintained. * **Radial Keratotomy (RK):** This is an obsolete surgical technique replaced by laser procedures. It is never performed on children and is associated with long-term complications like diurnal vision fluctuation and globe instability. **Clinical Pearls for NEET-PG:** * **Stability Rule:** Refractive surgery should only be performed after age 18 and once the refractive error has been stable for >1 year. * **Myopia Progression:** To slow progression in children, high-yield interventions include **Low-dose Atropine (0.01%)** and increased outdoor activity. * **High Myopia:** Defined as > -6.00D or axial length > 26.5 mm; it increases the risk of retinal detachment and macular degeneration.

Q: The prism produces displacement of the objects seen through it towards the:

Apex. ### Explanation **1. Why the Correct Answer is Right (Apex):** A prism is a transparent medium bounded by two non-parallel surfaces. When light passes through a prism, it obeys Snell’s Law and is refracted twice (at the entry and exit surfaces). Due to the geometry of the prism, light rays are always deviated **towards the base**. However, the human eye projects the image back along the path of the entering light rays. Because the rays reaching the eye are bent toward the base, the brain perceives the object as originating from a position shifted in the opposite direction. Therefore, the **image (displacement)** is always seen towards the **apex** of the prism. **2. Why the Incorrect Options are Wrong:** * **Option B (Base):** This is a common distractor. While the **light rays** are deviated towards the base, the **apparent displacement** of the object is towards the apex. * **Option C (Sideways):** Displacement is not random; it follows a specific geometric path determined by the apex-base relationship. Lateral displacement only occurs if the prism itself is rotated. * **Option D:** Incorrect, as there is a predictable optical shift. **3. Clinical Pearls & High-Yield Facts for NEET-PG:** * **Prism Diopter ($\Delta$):** Defined as a prism that produces a displacement of 1 cm at a distance of 1 meter. * **Prentice’s Rule:** $P = c \times F$ (where $P$ is prism power, $c$ is decentration in cm, and $F$ is lens power). This explains why looking through the periphery of a high-power lens induces a prismatic effect. * **Clinical Use:** Prisms are used to **measure** a squint (Prism Cover Test) and to **treat** diplopia (by moving the image toward the apex to fall on the macula of the deviated eye). * **Orientation:** In exotropia, we use a Base-In prism; in esotropia, we use a Base-Out prism.

Q: True regarding retinoscopy are all of the following except?

Hyperopes display an "against" movement. ### Explanation **Retinoscopy** (Skiascopy) is an objective method used to estimate the refractive error of the eye by neutralizing the movement of the red reflex. **Why Option D is the Correct Answer (The "Except" Statement):** In retinoscopy, the direction of the reflex movement depends on the patient's refractive state relative to the observer. When using a **plane mirror** at a standard distance (e.g., 1 meter): * **Hyperopia, Emmetropia, and Myopia 1D:** Displays an **"Against" movement** (reflex moves in the opposite direction). Therefore, the statement that hyperopes display an "against" movement is false. **Analysis of Other Options:** * **Option A:** Retinoscopy is the gold standard for **objective refraction**, especially in children or uncooperative patients, to estimate the power of the eye. * **Option B:** It is traditionally performed at **1 meter** (requiring a +1.0D correction) or **66 cm** (requiring a +1.5D correction). This distance is accounted for as the "working distance" constant. * **Option C:** A Priestley-Smith or reflecting retinoscope typically features a **plane mirror** on one side and a **concave mirror** on the other. Modern streak retinoscopes simulate these by moving the sleeve. **High-Yield Clinical Pearls for NEET-PG:** 1. **Neutralization Point:** The point where the pupil is filled with light and no movement is seen. 2. **Working Distance Formula:** $P = 1/d$ (where $d$ is distance in meters). For 66 cm, subtract 1.5D; for 1 m, subtract 1.0D from the gross value. 3. **Concave Mirror Rule:** If a concave mirror is used instead of a plane mirror, the movements are **reversed** (Hyperopes show "against," Myopes > 1D show "with"). 4. **Cycloplegics:** Atropine is preferred in children < 7 years; Homatropine for 7–15 years; Cyclopentolate or Tropicamide for adults.

Q: The total refractive power of the eye is normally 59 diopters. Two-thirds of this power is contributed by which ocular structure?

Anterior surface of the cornea. **Explanation:** The total refractive power of the human eye is approximately **+58 to +60 Diopters (D)**. This power is essential for focusing light rays onto the retina to form a clear image. **1. Why the Correct Answer is Right:** The **cornea** provides approximately **+43 D** (roughly two-thirds) of the eye's total refractive power. The majority of this refraction occurs at the **anterior surface of the cornea** because it represents the interface between two media with the greatest difference in refractive indices: **Air (1.00)** and the **Corneal Stroma/Tear Film (~1.376)**. According to Snell’s Law, the greater the change in refractive index, the greater the bending of light. **2. Why the Other Options are Incorrect:** * **Options A & B (The Lens):** The crystalline lens contributes the remaining one-third of the power (approx. **+15 to +20 D**). While the lens is crucial for accommodation, its refractive contribution is lower than the cornea because it is bathed in aqueous and vitreous humors, which have refractive indices (1.33) closer to that of the lens (1.39–1.40). * **Option D (Humors):** The aqueous and vitreous humors act as media through which light travels but do not possess significant intrinsic refractive power; they primarily maintain intraocular pressure and globe shape. **3. Clinical Pearls & High-Yield Facts for NEET-PG:** * **Refractive Indices:** Air (1.00), Cornea (1.376), Aqueous/Vitreous (1.336), Lens (1.39–1.40). * **Gullstrand’s Schematic Eye:** Total power is +58.64 D. * **Radius of Curvature:** The anterior surface of the cornea (~7.8 mm) is flatter than the posterior surface (~6.5 mm). * **Reduced Eye:** A simplified model where the eye is treated as a single refracting surface with a power of **+60 D** and a focal length of **17 mm** (in front of the retina).

Q: What is the angle subtended by the topmost letter in the Snellen's chart at the nodal point of the eye when the person is viewing it from 6 meters?

50 minutes. ### Explanation **1. Why Option D is Correct:** The Snellen’s chart is based on the principle of **minimum angle of resolution**. For a letter to be recognized, its components (strokes) must subtend an angle of **1 minute of arc** at the nodal point, and the letter as a whole must subtend an angle of **5 minutes of arc** at the standard distance. The topmost letter (usually 'E') is the **6/60 line**. This letter is designed to subtend an angle of 5 minutes when viewed from **60 meters**. However, in this question, the patient is viewing it from **6 meters**. Using the principle of proportionality: * At 60 meters, the letter subtends 5 minutes. * At 6 meters (1/10th the distance), the letter subtends 10 times the angle. * Calculation: $5 \text{ minutes} \times (60/6) = \mathbf{50 \text{ minutes}}$. **2. Why Other Options are Incorrect:** * **Option A (5 minutes):** This is the angle subtended by a letter at its **designated distance** (e.g., the 6/6 letter at 6 meters, or the 6/60 letter at 60 meters). * **Option B (10 minutes):** This would be the angle subtended by the 6/12 line letter when viewed from 6 meters ($5 \times 12/6$). * **Option C (40 minutes):** This would be the angle subtended by the 6/48 line letter when viewed from 6 meters. **3. Clinical Pearls & High-Yield Facts:** * **Standard Testing Distance:** 6 meters (20 feet) is used because light rays are considered parallel at this distance, requiring zero accommodation. * **The 5-Minute Rule:** Every Snellen letter is inscribed in a $5 \times 5$ grid. The whole letter subtends 5', while each individual block/gap subtends 1'. * **Visual Acuity Formula:** $V = d/D$, where '$d$' is the distance at which the patient reads the letter and '$D$' is the distance at which the letter subtends 5 minutes. * **LogMAR Chart:** Unlike Snellen, the LogMAR chart provides more accurate assessment in research because it has an equal number of letters per line and uniform spacing.

Q: One millimeter increase in the radius of curvature of the cornea leads to hypermetropia of:

6 dioptres. **Explanation:** The refractive power of the eye depends primarily on the axial length and the curvature of the cornea. The cornea provides approximately **43 to 44 Dioptres (D)** of the eye's total refractive power. The relationship between the radius of curvature ($r$) and refractive power ($P$) is governed by the formula for a spherical surface: $P = (n_2 - n_1) / r$. In the human eye, a **1 mm increase** in the radius of curvature (making the cornea flatter) results in a decrease in refractive power by approximately **6 Dioptres**. Because a flatter cornea fails to converge light sufficiently onto the retina, the focal point falls behind it, leading to **6D of hypermetropia**. **Analysis of Options:** * **Options A, B, and C (3D, 4D, 5D):** These values are incorrect because they underestimate the high refractive impact of the corneal surface. While a 1 mm change in *axial length* results in approximately 3D of refractive error, the *corneal curvature* has a much more potent effect per millimeter. * **Option D (6D):** This is the correct physiological constant. Conversely, a 1 mm *decrease* in the radius of curvature (steeper cornea) would lead to 6D of myopia. **Clinical Pearls for NEET-PG:** * **1 mm change in axial length** = 3 Dioptres of refractive error. * **1 mm change in corneal radius of curvature** = 6 Dioptres of refractive error. * **Average corneal radius of curvature:** 7.8 mm (Anterior surface). * **Keratometry:** The clinical procedure used to measure the corneal radius of curvature to calculate IOL power. * **Rule of Thumb:** For every 0.1 mm change in the radius of curvature, there is a 0.6D change in refractive power.

Q: Axial myopia is defined as:

Increase in the anteroposterior length of the eyeball. **Explanation:** Myopia (nearsightedness) occurs when the parallel rays of light coming from infinity are focused in front of the retina when accommodation is at rest. This refractive error can be classified based on the underlying anatomical cause: **1. Why Option A is Correct:** **Axial Myopia** is the most common clinical form. It occurs when the **anteroposterior (AP) length** of the eyeball is longer than normal, while the refractive power of the cornea and lens remains within normal limits. * **High-Yield Fact:** Every **1 mm increase** in axial length results in approximately **-3 Diopters** of myopia. **2. Why the Other Options are Incorrect:** * **Option B (Curvaturational Myopia):** This occurs when the curvature of the cornea or lens is increased (steeper). Examples include **Keratoconus** or Lenticonus. * **Option C (Positional Myopia):** This is caused by the **anterior displacement** of the crystalline lens (e.g., anterior subluxation), which increases the effective refractive power of the eye. * **Option D (Index Myopia):** This occurs due to an increase in the refractive index of the lens, typically seen in **nuclear sclerosis** (early stages of senile cataract). This often results in "second sight" in elderly patients. **Clinical Pearls for NEET-PG:** * **Normal Axial Length:** Approximately **24 mm** at birth. * **Pathological Myopia:** Also known as Degenerative Myopia, it is characterized by an axial length **>26.5 mm** and refractive error **>-6D**, often associated with posterior staphyloma and retinal lattice degeneration. * **Treatment of Choice:** Concave (minus) lenses, which diverge light rays to focus them precisely on the retina.

Question 1

Minus cylinder lenses are prescribed because of what reason?

Accepted Answer

They are preferred due to meridional aniseikonia.

Answer

They are cheaper to produce and distribute.

Answer

They reduce minification.

Answer

They cause less coma and trefoil.

Question 2

On performing retinoscopy, in which of the following conditions does the movement of the red reflex not occur with the movement of the retinoscope?

Accepted Answer

Myopia greater than 1 diopter

Answer

Emmetropia

Answer

Myopia less than 1 diopter

Answer

Hypermetropia

Question 3

What is the most accepted modality of treatment for 2D myopia in a 13-year-old girl?

Accepted Answer

Spectacles

Answer

Excimer laser

Answer

Contact lens

Answer

Radial keratotomy

Question 4

The prism produces displacement of the objects seen through it towards the:

Accepted Answer

Apex

Answer

Base

Answer

Sideways

Answer

None of the above

Question 5

True regarding retinoscopy are all of the following except?

Accepted Answer

Hyperopes display an "against" movement

Answer

Helps in estimating the condition of the refraction

Answer

Usually performed at 1 m distance

Answer

Consists of a plane and a concave mirror

Question 6

If the refractive power of the unaccommodated eye of an emmetropic woman is 60 diopters (D), what is the approximate axial length of her eye?

Accepted Answer

16.5 mm

Answer

14.5 mm

Answer

15.5 mm

Answer

17.5 mm

Question 7

The total refractive power of the eye is normally 59 diopters. Two-thirds of this power is contributed by which ocular structure?

Accepted Answer

Anterior surface of the cornea

Answer

Anterior surface of the lens

Answer

Posterior surface of the lens

Answer

Aqueous humor and vitreous humor combined

Question 8

What is the angle subtended by the topmost letter in the Snellen's chart at the nodal point of the eye when the person is viewing it from 6 meters?

Accepted Answer

50 minutes

Answer

5 minutes

Answer

10 minutes

Answer

40 minutes

Question 9

One millimeter increase in the radius of curvature of the cornea leads to hypermetropia of:

Accepted Answer

6 dioptres

Answer

3 dioptres

Answer

4 dioptres

Answer

5 dioptres

Question 10

Axial myopia is defined as:

Accepted Answer

Increase in the anteroposterior length of the eyeball

Answer

Increased curvature of the cornea

Answer

Anterior placement of the crystalline lens

Answer

Increase in the refractive index of the crystalline lens

Optics and Refraction — MCQs

Optics and Refraction — MCQs

On this page

Practice by Chapter

Want unlimited practice?